d^2-12d+20=

Solution for d^2-12d+20= equation:

Simplifying
d2 + -12d + 20 = 0

Reorder the terms:
20 + -12d + d2 = 0

Solving
20 + -12d + d2 = 0

Solving for variable 'd'.

Factor a trinomial.
(2 + -1d)(10 + -1d) = 0

Subproblem 1
Set the factor '(2 + -1d)' equal to zero and attempt to solve:

Simplifying
2 + -1d = 0

Solving
2 + -1d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1d = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1d = 0 + -2
-1d = 0 + -2

Combine like terms: 0 + -2 = -2
-1d = -2

Divide each side by '-1'.
d = 2

Simplifying
d = 2
Subproblem 2
Set the factor '(10 + -1d)' equal to zero and attempt to solve:

Simplifying
10 + -1d = 0

Solving
10 + -1d = 0

Move all terms containing d to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1d = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1d = 0 + -10
-1d = 0 + -10

Combine like terms: 0 + -10 = -10
-1d = -10

Divide each side by '-1'.
d = 10

Simplifying
d = 10
Solution
d = {2, 10}